b^2+56-35=3b

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Solution for b^2+56-35=3b equation:


Simplifying
b2 + 56 + -35 = 3b

Reorder the terms:
56 + -35 + b2 = 3b

Combine like terms: 56 + -35 = 21
21 + b2 = 3b

Solving
21 + b2 = 3b

Solving for variable 'b'.

Reorder the terms:
21 + -3b + b2 = 3b + -3b

Combine like terms: 3b + -3b = 0
21 + -3b + b2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-21' to each side of the equation.
21 + -3b + -21 + b2 = 0 + -21

Reorder the terms:
21 + -21 + -3b + b2 = 0 + -21

Combine like terms: 21 + -21 = 0
0 + -3b + b2 = 0 + -21
-3b + b2 = 0 + -21

Combine like terms: 0 + -21 = -21
-3b + b2 = -21

The b term is -3b.  Take half its coefficient (-1.5).
Square it (2.25) and add it to both sides.

Add '2.25' to each side of the equation.
-3b + 2.25 + b2 = -21 + 2.25

Reorder the terms:
2.25 + -3b + b2 = -21 + 2.25

Combine like terms: -21 + 2.25 = -18.75
2.25 + -3b + b2 = -18.75

Factor a perfect square on the left side:
(b + -1.5)(b + -1.5) = -18.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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